khan academy solving quadratic equations

#KHAN ACADEMY SOLVING QUADRATIC EQUATIONS PLUS#

We could say that b is equal to, and this is key, it's not just the 2, it's the negative 2. And so we can say that a is equal to 6, a is equal to 6. x squared, then x to the first, then the constant term. And, we have the x squared term first, then the x to the first power term, then the constant term. We have a zero on the right-hand side, we've done that. All of our terms, our non-zero terms are on the left-hand side, we've done that. So let's make sure we're already in standard form.

#KHAN ACADEMY SOLVING QUADRATIC EQUATIONS PLUS#

So let's add 6 to both sides.and then this simplifies to 6x squared, minus 2x, plus nine is equal to.zero. And now, to get rid of this negative 6 on the right-hand side, we can add 6 to both sides.

the 2 'x's on the right cancel out.equal to negative 6. 6x squared, and then we have minus 2x, and then we have plus 3 is equal to. And then I'll get.and I'm gonna write it in descending order for the exponents on x. so I could subtract 2x from both sides, so I could subtract 2x from both sides, so let me just.I'll take one step at a time. So essentially we wanna get everything on the left-hand side. We have 6x squared plus 3 is equal to 2x minus 6. So we have the x squared term and then the x term and then we have the constant term. So essentially you wanna get all of the terms on the left-hand side, and then we want to write them so that we have the x terms.where their exponents are in decreasing order. So standard form for a quadratic equation is ax squared plus bx plus c is equal to zero. Rewrite the equation 6x^2 + 3 = 2x - 6 in standard form and identify a, b, and c.

Khan academy solving quadratic equations